Page 1 of 1
Help with programming in VB6
Posted: Sat May 24, 2003 4:02 am
by Spamzor
update:
ok, i now have a completely working LCD program it runs in the background, needs some "jazzing" up, its usefull as long as you have the source -
http://members.optusnet.com.au/spamzor/FREE_LCD.zip
it displays CPU and RAM usage
its good for the basics a good starting point usefull if you need to start your own project
remember this was programmed for MY LCD and the source isnt to readable so let me know if you want to know something
Posted: Mon May 26, 2003 1:35 am
by Spamzor
ok, ive played around and worked out how it works, its a little confusing but heres what ive done now:
http://members.optusnet.com.au/spamzor/LCD_beta.zip
Posted: Wed May 28, 2003 2:41 am
by Spamzor
ok, im haveing troubles
i can turn my LCD backlight off
Code: Select all
MSComm1.Output = Chr$(&HFE) & Chr$(&H46)
but not on
Code: Select all
MSComm1.Output = Chr$(&HFE) & Chr$(&H4F) & Chr$(&H0)
i think its got something to do with the last segment
what SHOULD be there ?
Posted: Fri May 30, 2003 12:48 am
by Henry
I think you have a mistake...
MSComm1.Output = Chr$(&HFE) & Chr$(&H4F) & Chr$(&H0)
you said &H4F which is wrong, it should be &H42
Posted: Fri May 30, 2003 5:56 am
by Spamzor
omg !!!
i spent so long trying to work it out !
i had actually fixed that, but it wasnt saved (crashed)
argh !!!
thanks

Posted: Thu Jun 05, 2003 8:17 am
by Spamzor
ok update, check thread post
Posted: Fri Jul 04, 2003 1:04 pm
by dtorner
Henry wrote:I think you have a mistake...
MSComm1.Output = Chr$(&HFE) & Chr$(&H4F) & Chr$(&H0)
you said &H4F which is wrong, it should be &H42
I'm looking this thread and I'm confused about your Chr$ use... Why dont you use Chr$ like this (this code works OK) :
Public Function Light_On(Optional Minutos As Byte)
With MSComm1
.Output = Chr$(254)
.Output = Chr$(66)
If Minutos < 1 Or Minutos > 255 Then
.Output = Chr$(0)
Else
.Output = Chr$(Minutos)
End If
End With
End Function